Answer:
0.1828g/cm³
Explanation:
density= mass÷volume
m= 12.6g
v= 4.1×4.1×4.1 = 68.921cm³
•
density= 12.6÷68.921 = 0.1828g/cm³
Answer:
The two types of collisions are :
Type a)
<u>Elastic collision</u>
Type b)
<u>Inelastic collision</u>
Explanation:
Collision : It is the event when two bodies collide with each other for small period of time.
During collision , the bodies exert force to each other.
Example :
When boxer hits with punches .
When bat hits the ball in cricket match.
So, collision is short duration interaction of two objects. When the objects collides , there is change in their velocity.
All collision follow law of conservation of momentum . Their type is decided by , whether they follow conservation of energy also.
<u>Compare and contrast the two types</u>
a) Elastic collision : Those collision in which no loss or gain of kinetic energy will occur. They follow conservation of kinetic energy. Example : ideal gaseous molecule
b) Inelastic collision : Those collision in which Change in kinetic energy will occur. They do not follow conservation of kinetic energy.Almost all conservation are inelastic.
Here Kinetic energy get converted into other form of energy.
Explanation:
To out this fraction in its simplest form, you need to multiply the 8 by the 1 and then add the 1 in the numerator.
You end up getting
Answer:
Answer:
The correct answer is option d.
Explanation:
..[1]
..[2]
moles of sodium thiosulfate solution = n
Molarity of the sodium thiosulfate solution = 0.150 M
Volume of sodium thiosulfate solution used = 0.890 mL = 0.00089 L
According to reaction [2], 2 moles of sodium thiosulfate reacts with 1 mol 
.
Then , 0.0001335 mol of sodium thiosulfate will reacts with:
of
Moles of = 0.00006675 mol
According to reaction [1], 1 mol of is obatnied from 1 mol of NaClO.
Then 0.00006675 mol of will be obtained from:
Mass of 0.00006675 mol of NaClO=
0.00006675 mol × 74.44 g/mol = 0.00496887 g
Mass of sample = 0.0854 g
Percentage of NaClO in sample:
Answer:
126 grams
Explanation:
What is the mass of two moles of HNO3?
H = 1g/mole = 1+
N = 14g/mole = 3-
O = 16g/mole = 2-
HNO3 = 63g/mole
