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2 years ago

What did Bohi's model of the dom inchide that Ruthextends model did not have

Physics

1 answer:

Aleksandr-060686 [28]2 years ago

6 0

Answer:

Electrons revolves around the nucleus in a fixed orbits with fixed energy.

electron clouds.

Explanation:

Rutherford in his model of atom explained:

Maximum space inside the atom is empty.

Electron revolves around the the center called nucleus.

Nucleus contains the positive charge.

Bohr's in his model explained that:

Electrons revolves around the nucleus in a fixed orbit named as shells.

Each orbits or shells has fixed amount of energy and size.

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2 years ago

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. Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.

anastassius [24]

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Two identical conducting spheres, A and B, carry equal charge. They are stationary and are separated by a distance much larger t

podryga [215]

Answer:

8F_i = 3F_f

Explanation:

When two identical spheres are touched to each other, they equally share the total charge. Therefore, When neutral C is first touch to A, they share the initial charge of A equally.

Let us denote that the initial charge of A and B are Q. Then after C is touched to A, their respective charges are Q/2.

Then, C is touched to B, and they share the total charge of Q + Q/2 = 3Q/2. Their respective charges afterwards is 3Q/4 each.

The electrostatic force, Fi, in the initial configuration can be calculated as follows.

$F_i = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{Q^2}{r^2}[/tex}The electrostatic force, Ff, in the final configuration is [tex]F_f = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{3Q^2/8}{r^2}[/tex}Therefore, the relation between Fi and Ff is as follows[tex]F_i = F_f\frac{3}{8}\\8F_i = 3F_f$

7 0

3 years ago

Can someone help??

Paul [167]

Answer:

F = 2520 N

Explanation:

We have,

The maximum acceleration of a fist in a karate punch is 4200 m/s². The mass of the fist is 0.6 kg.

It is required to find the force that the wood place on the fist. Force is given by the product of mass and its acceleration such that,

F = ma

$F=0.6\times 4200\\\\F=2520\ N$

So, the force of 2520 N is acting on the wood.

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2 years ago