Answer:
Step-by-step explanation:
a) P(80 < X < 110) for N(100,15)
Mean 100 sd=15
z F (x)
80 -1.333333333 0.09121122
110 0.666666667 0.747507462
P(80<x<110) 0.656296243
b. P(1.50 < X < 2.00) for N(0,1)
z F (x)
1.5 0.933192799
2 0.977249868
P(1.50 < X < 2.00) =0.04406
c. P(4,500 < X < 7,000) for N(6000,1000)
6000 1000
z F (x)
4500 -1.5 0.066807201
7000 1 0.841344746
P(4500<x<7000) 0.774537545
d. P(225 < X < 450) for N(600,100)
600 100
z F (x)
225 -3.75 8.84173E-05
450 -1.5 0.066807201
P(225<x<450) 0.066718784