The cost of each Piano Lesson = $30
If there are x lessons, the total cost of lessons can be expressed as 30x.
Since the number of lessons cannot be negative, the value of x can be 0 or greater than 0, where x=0 shows no lesson.
For 1 lesson, x = 1
So the cost will be = 30(1) = $30
In ordered pair we can write it as (1, 30)
If we consider there is an option to attend half portion of a lecture, then for 1 and half lectures, x = 1.5
So, the cost for 1.5 lectures will be = 30(1.5) = $45
In ordered pair we can write it as (1.5, 45)
For 3 lesson, x = 3
The cost of 3 lessons will be = $90
In ordered pair we can write this as (3, 90)
So, from the given options, only following 2 ordered pairs satisfy the given conditions:
1) (1,30)
2) (3, 90)
Volume of the 1st package : 8.5x11x2 =187 in³
Volume of the 2nd package = 17.5x12x10 = 2,100 in³
Number of packages that fit = V₂/V₁ = 2100/187 = 11.23 Packages
Answer:
water + vinegar = 24 oz
W + V = 24
Also, we know V = 2 W add 2 parts of vinegar to 1 part water
2W + W = 24 oz
W = 8 oz
V = 16 oz amounts to add
A factorization of is .
<h3>What are the properties of roots of a polynomial?</h3>
- The maximum number of roots of a polynomial of degree is .
- For a polynomial with real coefficients, the roots can be real or complex.
- The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if is a root, then is also a root.
If the roots of the polynomial are , then it can be factorized as .
Here, we are to find a factorization of . Also, given that and are roots of the polynomial.
Since is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.
Hence, and are also roots of the given polynomial.
Thus, all the four roots of the polynomial , are: .
So, the polynomial can be factorized as follows:
Therefore, a factorization of is .
To know more about factorization, refer: brainly.com/question/25829061
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