Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Person has the flu.
- Event B: Person got the flu shot.
The percentages associated with getting the flu are:
- 20% of 30%(got the shot).
- 65% of 70%(did not get the shot).
Hence:
The probability of both having the flu and getting the shot is:
Hence, the conditional probability is:
0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
To learn more about conditional probability, you can take a look at brainly.com/question/14398287
Answer:
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Step-by-step explanation:
Multiply through by 6 to eliminate the fraction
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Move - 18f³ to the right side of the equation
That's
Divide both sides by M to make B stand alone
That's
We have the final answer as
Hope this helps you
Answer:
C
Step-by-step explanation:
Divide the household with pet rabbits by the total number of household in the U.S. to get the proportion of U.S. households with pet rabbits. Then, convert the proportion to a percentage.
6,678,000/126,200,000 ≈ 0.05 = 5%
Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
8+x = 22
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