You would want to make sure that you have controlled the variables properly, and if you determine that you did then you would repeat the experiment to be sure of the results.
94.6 g. You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.
We can use a version of the <em>dilution formula</em>
<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2
where
<em>m</em> represents the mass and
<em>C</em> represents the percent concentrations
We can rearrange the formula to get
<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)
<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %
<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %
∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g
Answer:
1. Nonmetals.
2. Likely to form anions (except the noble gases).
3. All of these
4. Easily reduced (except the noble gases).
Explanation:
Elements with high electronegativities are found towards the upper right corner of the Periodic Table. Thus, they have all the above properties.
Answer:
the volume delivered by the pipette = 22.32 mL
Explanation:
To calculate this, let us first note that the density of water relates it weight and its volume (density = mass ÷ volume), hence we are going to use density to determine the volume.
Density of water = mass/volume = 0.997 g/ mL
mass = 22.25g
Density = 0.997g/mL
volume = ?
∴ the volume delivered by the pipette = 22.32 mL
<em>Please note that this calculation is based on the fact that the weight of the empty flask has been determined and canceled out.</em>