Answer:
in 13.95 years the senior class will have 100 students.
Step-by-step explanation:
P(h) = p(0.92)^t (equation for exponential change)
P(h) - population of highschool (or senior class) = 100
p - staring amount = 320
t = time in years
100 = 320(0.92)^t
1/3.2 = .92^t (divide both sides by 320)
log(1/3.2, .92) = t (log base 0.92 of 1/3.2 equals t)
13.9497 = t
Percentage by which the average value of mid sized car decreases each year = 8%
Retail value of a car today = v dollars
Amount of decrease in the value of the car after 1 year = (8/100) * v
= 2v/25 dollars
Then
The equation that represents the value of the car after 1 year = v - (2v/25) dollars
= (25v - 2v)/25 dollars
= 23v/25 dollars
So following this expression the value of the mid sized car can be easily determined after 1 year. I hope this is the answer you were looking for and the procedure is also clear to you.
Answer:
Step-by-step explanation:
a+s=14
a=14-s
a+8s=56, using a from above in this equation gives
14-s+8s=56
14+7s=56
7s=42
s=6
a=14-s
a=14-6=8
So student tickets cost $6 and adult tickets cost $8.
Equation- l=65-15d
graph- discrete bc it's only for integer numbers