Answer: The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.
Step-by-step explanation:
Order the dataset from least to greatest:
-38 → -13 → -9 → -2 → 14 → 28
Then find the values that lies in the middle:
-38 → -13 → <u>-9 → -2</u> → 14 → 28
Since there are 2 values, find the average of those 2 values:
The median value = -5.5.
The median value of data set B is -5.5, which is less than the median value of 3.1 in dataset A.
Answer:
answer is D
Step-by-step explanation:
because to even it out, you would need ore ones to have rolled to make an average
Answer:
x=5.6
y=-5.6
Step-by-step explanation:
3x - 5y = 14 Equation 1
– 2x + 2y = 0 Equation 2
Simultaneous equation can be solved either through elimination method or substitution method. But we use elimination method for this question
Multiply equation 1 by -2 (the coefficient of x in equation 2) and multiply equation 2 with 3 (the coefficient of x in equation 1), so that x will have the same coefficient in the new equations, and easy to eliminate
-2(3x - 5y = 14)
-6x+10y=-28 Equation 3
3(– 2x + 2y = 0)
-6x+6y=0 Equation 4
Subtract equation 4 from 3 to eliminate x
-6x+10y=-28
-6x+6y=0
-6x-(-6x)=-6x+6x=0
10y-6y=5y
-28-0=-28
5y=-28
y=-28/5
y=-5.6
Substitute for y in equation 2
– 2x + 2y = 0
– 2x + 2(-5.6) = 0
-2x-11.2=0
-2x=11.2
x=-11.2/2
x=5.6
Answer: 7 miles, (I'm pretty sure)
Step-by-step explanation:
Answer:
P(X>17) = 0.979
Step-by-step explanation:
Probability that a camera is defective, p = 3% = 3/100 = 0.03
20 cameras were randomly selected.i.e sample size, n = 20
Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97
Probability that more than 17 cameras are working P ( X > 17)
This is a binomial distribution P(X = r)
P(X>17) = P(X=18) + P(X=19) + P(X=20)
P(X=18) =
P(X=18) =
P(X=18) = 0.0988
P(X=19) =
P(X=19) =
P(X=19) = 0.3364
P(X=20) =
P(X=20) =
P(X=20) = 0.5438
P(X>17) = 0.0988 + 0.3364 + 0.5438
P(X>17) = 0.979
The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch