Answer:
f(2) = 12
f(x) = 7, x = -3, 1
Step-by-step explanation:
<u>a)</u>
plug in x as 2
f(x) = 2^2 + 2(2) + 4
f(x) = 4 + 4 + 4
f(x) = 12
<u>b)</u>
replace f(x) with 7
7 = x^2 + 2x + 4
x^2 + 2x - 3 (move 7 to other side)
Factor
ac: -3x^2
b: 2x
split b into 3x, -x
(x^2 -x) + (3x - 3)
↓ ↓
x(x-1) + 3(x-1)
Factor: (x-1)(x+3) = 0
Solve using Zero Product Property:
x - 1 = 0, x + 3 = 0
x = 1, x = -3
Answer:
95 city and 175 highway miles.
Step-by-step explanation:
The driver gets 20 mpg in city, and 28 mpg on the highway.
An equation that could be written is
20x+28y=270
This equation accounts for the distance traveled.
x+y=11
This equotion accounts for how many gallons were driven.
Multiply the bottom equation by 20, so you can solve the set of equations.
20x+28y=270
20x+20y=220
subtract them
8y=50
y=6.25
now plug this back into x+y=11
x+6.25=11
x=4.75
Now 4.75×20=95 city miles and 6.25×28=175 highway miles.
Answer:
20
Step-by-step explanation:
i think but not fur shure
4 Options bc its correct ome