Answer:
$6.07/hr. if I understand the question properly. See below.
Step-by-step explanation:
I don't see the question, but will assume we want to find Larisa's base pay. The $7/hr given is the average for the work sequence noted in the problem. If this is incorrect, ignore the answer.
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Let x be Larisa's base salary. We are told, I think, that in one stretch of time Larisa earned an average of $7/hour. That was composed of:
<u>Hours</u> <u>Rate($/hr)</u>
40 x
3 1.5x
<u> 6 </u> 2x
49
Her total income over this period would be:
40x +3(1.5x) + 6(2x) [The hours worked times the pay rate for each period]
Her average income per hour would be:
(40x +3(1.5x) + 6(2x))/49
which we are told is $7/hr.
(40x +3(1.5x) + 6(2x))/49 = 7
40x + 4.5x + 12x = 343
56.5x = 343
x = $6.07/hr
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx