Answer:
a the mother is heterozygous so Aa
b would be aa
c. 50% as she could either get the dominant allele from her mother or not it is a coin flip
Explanation:for c the best way to do that one is to draw a punnitt square
Answer:
Explanation:
In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case 
) and the anion is the atom at the right of the name (in this case 
). With this in mind, the <u>formula would be</u> 
.
Now, if we used <u>metallic copper</u> we have to put in the reaction only the <u>copper atom symbol</u> 
. So, we have as reagents:
The question now is: <u>What would be the products?</u> To answer this, we have to remember <u>"single displacement reactions"</u>. With a general reaction:
With this in mind, the reaction would be:
I hope it helps!
If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
Oxygen gas produced : 0.7 g
<h3>Further explanation</h3>
Given
10.0 grams HgO
9.3 grams Hg
Required
Oxygen gas produced
Solution
Reaction⇒Decomposition
2HgO(s)⇒2Hg(l)+O₂(g)
Conservation of mass applies to a closed system, where the masses before and after the reaction are the same
mass of reactants = mass of products
mass HgO = mass Hg + mass O₂
10 g = 9.3 g + mass O₂
mass O₂ = 0.7 g
Just to make sure I’m right, is number 1 miss spelled??
