A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
1 answer:
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Answer:
F' = 64 F
Explanation:
The electric force between charges is given by :
Where
q₁ and q₂ are charges
r is the distance between charges
When each charge is doubled and the distance between them is 1/4 its original magnitude such that,
q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)
New force,
Apply new values,
So, the new force becomes 64 times the initial force.