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2 years ago

The graph shows the relationship between the weight of an object on the moon and its weight on Earth.

Mathematics

2 answers:

OLEGan [10]2 years ago

4 0

Answer:

It would have to be B: 6

Step-by-step explanation:

I would say this because I just did a quiz about it. Sorry for no explanation.

shtirl [24]2 years ago

4 0

Answer:

The answer is d

Step-by-step explanation:

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If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

Sauron [17]

<h2>Answer:</h2>

$2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}$

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

$\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)$

So we need to find two things:

$2\vec{v}-6\vec{u}$

and:

$||2\vec{v}-6\vec{u}||$

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

$2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}$

SECOND:

If we name:

$\vec{w}=2\vec{v}-6\vec{u}$

Then, $||2\vec{v}-6\vec{u}||$ is the magnitude of the vector $\vec{w}$ . Therefore:

$||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}$

5 0

2 years ago

Read 2 more answers

Match each number with its place in order from smallest (1st) to largest (6th).

zheka24 [161]

90 would be the largest then 59,48, -56, -80, and leaving -84 to be the smallest

8 0

2 years ago

Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1

elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0

2 years ago

Find the diameter of a circle with a radius of 13 ft.

Blizzard [7]

Answer:

Step-by-step explanation:

A radius is half of a diameter so multiply by 2

3 0

2 years ago

Find the next two terms. 81, 27, 9, ?, ?

Nataly_w [17]

Answer:

3 and 1

Step-by-step explanation:

Similarly each term is 1/3 of the previous term. This is a geometric sequence.

9/3 = 3

3/3 =1

3 0

1 year ago