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2 years ago

12

Bertha has 6 marbles, and Sheniqwa has 9 marbles. What is the difference between the amount of marbles Bertha has and the amount

that Sheniqwa has?

2 answers:

Evgesh-ka [11]2 years ago

8 0

The answer is 3 marbles

atroni [7]2 years ago

3 0

3marbles is the difference

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If B equals 7 what is the value of the expression 2 + (10 - B )?

avanturin [10]

We just need to <u>plug in 7 for B! </u>

Let's do it !

2 + (10 - 7)

<em>We always start with the parenthesis first ! It's just a rule in math :) </em>

10 - 7 = ?

10 - 7 = 3

Now we have ...

2 + 3

2 + 3 = 5

Your final answer is 5!

I hope I helped :) Just comment if you have any questions and remember to vote me "brainliest" if you like my answer !!!

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Could help if you showed the rest of the table

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Which of the following represents the most accurate estimation of 54-16?=

sukhopar [10]

You didn't tell us what the choices are, so there's
nothing to pick from.

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Plz help I’ll pay I promise this is timed

Wewaii [24]

Answer:

you can say u are mutiplying them by two each times see

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Step-by-step explanation:

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What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

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2 years ago