Answer: d) DF ≅ JH
<u>Step-by-step explanation:</u>
Side-Side-Side Congruency Theorem states that triangles are congruent if and only if their corresponding side lengths are congruent.
Given: EF ≅HI
Given: DE ≅IJ
Missing: DF ≅ JH
Answer:
Try solving 6(n-5)-2.
Step-by-step explanation:
I believe this can be set up as 6(n-5)-2. The difference of a number and five can be represented by n-5. If this needs to be multiplied by 6 (hence 6 times), it would become 6(n-5). Two less than that is represented by -2. Thus, two less than six times the difference of a number and five is 6(n-5) -2, which, when n=9 is plugged in, looks like 6(9-5) -2. Follow PEMDAS from there.
Answer:4 in each package
Step-by-step explanation:
Answer:
x = -1, y = -2.
Step-by-step explanation:
Using the elimination method,
multiply the first eqn by 2 and the 2nd eqn by 5.
6x - 10y = 14
25x - 10y = -5
Subtract one of the new equations from the other
-19x = 19
x = -1
Sub x=-1 into the 2nd eqn
-5 - 2y = -1
y = -2
Hence x = -1, y = -2.
