Answer:
E=1824.81 V/m
Explanation:
Given that
Voltage difference = 5 V
Distance ,D= 3 mm
θ = 24°
As we know that electric filed given as
Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.
d= D cosθ
d= 3 cos24°
d = 2.74 mm
So
E=1824.81 V/m
Answer:
73325J
Explanation:
Given parameters:
Mass of water = 0.5kg
Initial temperature = 30°C
Final temperature = 65°C
Specific heat capacity = 4190J/kg°C
Unknown:
Amount of energy absorbed = ?
Solution:
The amount of energy absorbed can be derived using the expression below;
H = m c Δt
H is the amount of energy
m is the mass
c is the specific heat
Δt is the change in temperature
H = 0.5 x 4190 x (65 - 30 )
H = 73325J
<span>(a)
Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get:
18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component.
(b)
To much the same end do we derive the vertical component:
18.0*sin37.5 = v_y = 10.96 ms^-1
Which we then divide by acceleration, a_y, to derive the time till maximal displacement,
10.96/9.8 = 1.12 s
Finally, doubling this value should yield the particle's total time with r_y > 0
<span>2.24 s
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Answer:s=0.68 m
Explanation:
Given
Inclination
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using
Final velocity v=0
s=0.68 m