The question is incomplete. The complete question is :
In a certain underdamped RLC circuit, the voltage across the capacitor decreases in one cycle from 5.0 V to 3.8 V. The period of the oscillations is 1.2 microseconds (1.2*10^-6). What is Q?
Solution :
The underdamped RLC circuit
We know in one time period, v = 2v, at t = T,
so,
Now, Q value
∴
= 11.45
<span>Charging by friction occurs, Electrons are transferred when one object rubs against another.
Another example of this would be socks on carpet.
Hope this helps!</span>
Resistance = (voltage) / (Current)
Resistance = (10 V) / (5 A)
Resistance = 2 ohms.
Answer:
No, you can't keep on dividing the charge forever.
Explanation:
No, you can't keep on dividing the charge in that manner forever because the total charge of the stick is an integer multiples of individual units known as an elementary charge, <em>which is the electron (e) charge (e = 1.602x10⁻¹⁹C)</em>.
Therefore the limit of the division of the original charge will be the electron charge since it is the smallest charge that can exist freely.
I hope it helps you!