Answer:
3.
D. Philippine Atmospheric, Geophysical and Astronomical Services
Administration (PAGASA)
Explanation:
4.C. 62.0 kph
Answer:
0.0613 L
Explanation:
Given data
- Initial pressure (P₁): 1.00 atm
- Initial volume (V₁): 1.84 L
- Final pressure (P₂): 30.0 atm
Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1.00 atm × 1.84 L / 30.0 atm
V₂ = 0.0613 L
The density of ice is less than the density of water (liquid). We generally observe that the density of a solid substance is more than its liquid form as volume of a solid is generally less than the liquid, However in case of water this is not true.
The volume of ice is less than that of liquid water due to an open cage like structure in ice which gives its a wide structure. This cage like structure is due to presence of hydrogen bond (more extensive) in ice.
The maximum density of water is observed at 4 degree celsius
Answer:
6.14 L
Explanation:
To answer this question we'll<u> use the PV=nRT formula</u>, where:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 17.6 °C ⇒ 17.6 + 273.16 = 209.76 K
We <u>input the data</u>:
- 0.97 atm * V = 0.25 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 209.76 K
And <u>solve for V</u>:
