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2 years ago

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Targe

1 answer:

Hatshy [7]2 years ago

4 0

Idk math but I can sell come thru for that low

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Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago

Point M is located in the third quadrant of the coordinate plane, as shown.

Angelina_Jolie [31]

(-5.5,2) is the answer

4 0

2 years ago

Read 2 more answers

WILL MARK BRAINIEST! 25 POINTS! What is 2^4/3 equal to? ∛8 ²√8 ∛16 ²√16 Please show work, i need to understand this

Mariana [72]

Answer:

∛16

Step-by-step explanation:

2^4/3

2^4 = 16

Then 16^1/3

∛16

4 0

2 years ago

Read 2 more answers

There were three concerts in Lakeside. The first concert had 953 people in the attendance. The second and third concerts each ha

earnstyle [38]

953 + 1100 + 1100 = 3153
3153 / 3 = 1051

3 0

2 years ago

What is -5/4 to the 2nd power?

Vsevolod [243]

Answer:

$\frac{25}{16}$

Step-by-step explanation:

$(-\frac{5}{4})^2\\\\ \text {Apply power of a fraction rule: } (\frac{a}{b})^x=\frac{a^x}{b^x}\\\\(-\frac{5}{4})^2 = \frac{-5^2}{4^2}=\frac{25}{16}\\\\\boxed{(-\frac{5}{4})^2=\frac{25}{16}}$

8 0

2 years ago