The zeros of a quadratic function are found where the graph intersects the x-axis. If the graph interects the x-axis in 2 places, we have 2 real solutions; if the graph intersects--or just touches--the x-axis in one place we have one real solution multiplicity 2; if the graph doesn't go through the x-axis at all we have 2 imaginary solutions. Ours goes through the x-axis in 2 places so we have 2 real solutions. Choice A.
Elaine's piece is bigger because when you look at the tenths place, you can see that 1 is bigger than 0.
Answer:1750
Step-by-step explanation:
From the two right triangles, you can write the following equations using the Pythagorean theorem. Let's call that shared leg in the middle "y"
y^2 + b^2 = a^2
y^2 + c^2 = x^2
y^2 + b^2 = a^2
re-write this to get "y" alone for substitution.
y^2 = a^2 - b^2
substitute (a^2 - b^2) for y^2 in the other equation. y^2 + c^2 = x^2
a^2 - b^2 + c^2 = x^2
Now put in the values given for a,b,c to solve for x
(7.1)^2 - (5.6)^2 + (5.7)^2 = x^2
51.54 = x^2
square root
7.2 = x