It will be a horizontal line at y=7 and shaded above. If you have pictures of the graph I can show which one it would be.
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Answer:
6x^2 +x -12
Step-by-step explanation:
Substitute for A and B and collect terms.
2B +3A
= 2(3x^2 -x +3) +3(x -6) . . . . substitute for A and B
= 6x^2 -2x +6 +3x -18 . . . . . eliminate parentheses
= 6x^2 +x -12 . . . . . . . . . . . . collect terms
Answer:
Step-by-step explanation:
x² - 2x + y² - 4y - 4 = 0
x² - 2x + y² - 4y = 4
complete the squares
(x² - 2x + x₀) + (y² - 4y + y₀) = 4
the unknown number will be the square of half of the x¹ coefficient
(x² - 2x + 1) + (y² - 4y + 4) = 4 + 1 + 4
(x - 1)² + (y - 2)² = 9
This tells us that the circle is centered on (1, 2)
Which is also a point on the diameter
2x - y + a = 0
a = y - 2x
a = 2 - 2(1)
a = 0
To solve this you have to divide 90 by 10 which would be 9 so
t=9
Hope it helps