Plzzz hurry up and help me if A+B=45prove that (1+tanA)(1+tanB)=2
1 answer:
Answer:
see explanation
Step-by-step explanation:
If A +B = 45° then tan(A+B) = tan45° = 1
Expanding (1 + tanA)(1 + tanB)
= 1 + tanA + tanB + tanAtanB → (1)
Using the Addition formula for tan(A + B)
tan(A+B) = = 1 ← from above
Hence
tanA + tanB = 1 - tanAtanB ( add tanAtanB to both sides )
tanA + tanB + tanAtanB = 1 ( add 1 to both sides )
1 + tanA + tanB + tanAtanB = 2
Then from (1)
(1 + tanA)(1 + tanB) = 2 ⇒ proven
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Answer:
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Step-by-step explanation:
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A: x=0, y=10, then from the equality follows that A lies on the line.
B: x=3, y=13, then from the equality follows that B lies on the line.
C: x=8, y=2, then from the inequality follows that C doesn't lie on the line.
D: x=5, y=15, then from the equality follows that D lies on the line.