Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
Here are the values of the first 5 terms of 3 sequences: : 30, 40, 50, 60, 70, . . . : 0, 5, 15, 30, 50, . . . : 1, 2, 4, 8, 16,
Levart [38]
Answer:
1,2,4,8,16.
Step-by-step explanation:
they are a square root of 2 for each question. it will eventually get up higher then additive.
Uh do you mean he earned $225 per week?
If yes, then he earned 45 per day.
Answer:
x = -10/13
Step-by-step explanation:
10x + 7 = -3x - 3
Add 3x to both sides
10x + 3x + 7 = -3x + 3x - 3
13x + 7 = 0x - 3
13x + 7 = -3
Subtract 7 from both sides
13x + 7 - 7 = -3 - 7
13x + 0 = -10
13x = -10
Divide both sides by 13
13x ÷ 13 = -10 ÷ 13
1x = -10/13
x = -10/13
Answer:
Step-by-step explanation:
That is 3 to the 4th power
