Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
234
Step-by-step explanation:
We want to find the summation from n = 2 to n = 10 of the equation -4 + 5n.
We can use the summation formula:
, where a1 is the first term, is the last term, and n is the number of terms
Here, we can say the first term occurs when n = 2:
-4 + 5n
-4 + 5 * 2 = -4 + 10 = 6
The last term will be when n = 10:
-4 + 5n
-4 + 5 * 10 = -4 + 50 = 46
The number of terms is just 10 - 2 + 1 = 9 terms.
Substitute these in:
Thus, the answer is 234.
Answer: 20. 4, 3, 2, 1...
21. 17....
Step-by-step explanation:
Answer:
A= H<u>b B
</u>
2
Step-by-step explanation:
Q16- = A=75
cm
Q17- = A=10in
Q18- = A=70
a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
Learn more about perimeter of quarter circle on:
brainly.com/question/15976233