2 years ago

What is the empirical formula and empirical formula mass for the following compound? C3H6O3?

Chemistry

1 answer:

babunello [35]2 years ago

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Answer: C3H6O3 > CH2O

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Volume occupied by the one atom: $\frac{4}{3}\pi r^3$

$=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3$

given that $2.69\times 10^{22}$ atoms are present in 1L

1 L = 0.001 $m^3$

The volume occupied by the $2.69\times 10^{22}$ neon atoms

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Fraction of volume occupied by the neon atom:

$=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3$

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The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

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