I believe the answer is 3
Answer:
diagonal = = 12.8 inches (to the nearest tenth of an inch)
Step-by-step explanation:
As shown in the diagram attached to this solution:
Let the Length of the rectangular board = a
Let the width = b
Let the diagonal = d
where:
a = 10 inches
b = 8 inches
d = ?
Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:
(hypotenuse)² = (Adjacent)² + (Opposite)²
d² = 10² + 8²
d² = 100 + 64
d² = 164
∴ d = √(164)
d = 12.806 inches
d = 12.8 inches (to the nearest tenth of an inch)
<em>N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.</em>
Answer:
7.8
Step-by-step explanation:
Answer:
3: 2q − 4 = 20
Step-by-step explanation:
Solve for q:
2 q - 4 = 20
Add 4 to both sides:
2 q + (4 - 4) = 4 + 20
4 - 4 = 0:
2 q = 20 + 4
20 + 4 = 24:
2 q = 24
Divide both sides of 2 q = 24 by 2:
(2 q)/2 = 24/2
2/2 = 1:
q = 24/2
The gcd of 24 and 2 is 2, so 24/2 = (2×12)/(2×1) = 2/2×12 = 12:
Answer: q = 12