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2 years ago

11

Each digit in the division example. Has been replaced. With the. Same letter. Throughout. R stand for remainder. The digits used

were 1 2 3 4 5 7 8 and 9 find the numbers clue-U is 5

1 answer:

Trava [24]2 years ago

5 0

The answer to your question is 6

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Tell which value of the variable is the solution of the equation. 6c=96; c=14,15,16,17

otez555 [7]

Answer:

c = 16

Explanation:

Do it on a calculator it'll be correct

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2 years ago

Wholesale price of coffeemaker = $31.55<br>Percentage markup = 17%<br>Retail price?

serious [3.7K]

Answer:

$36.9135

Step-by-step explanation:

Markup = 17% of 31.55

= 17/100 × 31.55

= 5.3635

Retail price = whole sale price + markup

= 31.55 + 5.3635

= $36.9135

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2 years ago

HELP !!! Evaluate f(-2) for the function f(x) = 3x2 + 2x - 5

Phoenix [80]

Answer:

3

Step-by-step explanation:

So we have the function:

$f(x)=3x^2+2x-5$

To evaluate the value of f(-2), substitute -2 for x. Thus:

$f(-2)=3(-2)^2+2(-2)-5$

Square first:

$f(-2)=3(4)+2(-2)-5$

Multiply:

$f(-2)=12-4-5$

Now, subtract:

$f(-2)=8-5=3$

So:

$f(-2)=3$

And we're done!

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2 years ago

I need help with my homework plis<br> Box Plots

kolbaska11 [484]

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2 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

frosja888 [35]

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.327$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.08, \sigma = \sqrt{1.21} = 1.1$ .

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.327*\frac{1.1}{\sqrt{n}}$

$0.08\sqrt{n} = 2.327*1.1$

$\sqrt{n} = \frac{2.327*1.1}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}$

$n = 1024$

The minimum sample size required to create the specified confidence interval is 1024.

3 0

3 years ago