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2 years ago

Simplify and expand (1/3)to 2nd power × 18 + (1/2)to 2nd power × 4

1 answer:

6 0

Step 1. Use Division Distributive Property $( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }$

Step 2. Simplify $3^{2}$ to $9$

$\frac{1}{9} *18+( \frac{1}{2} ) ^{2}*4 
$

Step 3. Use Division Distributive Property $( \frac{x}{y} ) ^{a} = \frac{ x^{a} }{ y^{a} }$

$\frac{1}{9} *18+ \frac{1}{ 2^{2} } *4$

Step 4. Simplify $2^{2}$ to $4$

$\frac{1}{9} *18+ \frac{1}{4} *4$

Step 5. Simplify $\frac{1}{9} *18$ to $\frac{18}{9}$

$\frac{18}{9} + \frac{1}{4} *4$

Step 6. Simplify $\frac{18}{9}$ to $2$

$2+ \frac{1}{4} *4$

Step 7. Simplify $\frac{1}{4} *4$ to $1$

$2+1$

Step 8. Simplify

$3$

Done! Your answer is 3

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The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x

Mariulka [41]

Answer:

-3,5

Step-by-step explanation:

$d = \sqrt{(x _{2} - x _1) {}^{2} + (y _{2} - y _{1} {} ) {}^{2} }$

$5 = \sqrt{(x - 1) {}^{2} + ( - 1 - 2) {}^{2} }$

$5 = \sqrt{(x - 1) {}^{2} + ( - 3) {}^{2} }$

$25 = (x - 1) {}^{2} + 9$

$16 = (x - 1) {}^{2}$

$4 = x - 1$

$x = 5$

$- 4 = x - 1$

$x = - 3$

7 0

1 year ago

HEEEEEELPPPPPPPPP!!!!!!!!!!!!!

lions [1.4K]

B is the right answer

5 0

2 years ago

I need help with this, please!

Karo-lina-s [1.5K]

Answer:

D. x≥3 

Step-by-step explanation:

☜☆☞ given equation..... 3x-1 ≥ 8

–» 3x ≥ 8+1

–» 3x ≥ 9

–» x ≥ 9÷3

–» x ≥ 3

6 0

2 years ago

Read 2 more answers

Consider the relation R on the set S = {1, 2, 3, 4} defined by

Nataly [62]

Answer:

Step-by-step explanation:

a) A relation R is symmetric when it includes the inverse relation, for example if it includes (8,9) then it should also include (9,8), if not, then the relation is not symmetric, you can see that in this case the relation includes (3,4) but not (4,3), therefore it is not symmetric

b) A relation is antisymmetric when it never includes the inverse relation, for example if it includes (8,9) then it can not include (9,8), if it does then it is not antisymmetric. In this case you can see that it first starts with (1,2) but then it also includes (2,1) so then it is not antisymmetric

c) A relation is reflexive if for each number of the domain set it includes the pair that is two times that same number, for example if 8 is in the domain then the relation should include (8,8). if not then it is not reflexive. In this case you can see that the domain S includes 1 but (1,1) is never on the relation or for example (2,2) is also never in the relation.

4 0

2 years ago

transmission channel operates at 3Mbps and has a bit error rate of 10^(-3). Bit errors occur at random and independent of each o

marysya [2.9K]

Answer:

$1001\times 10^{-7}\%$

Step-by-step explanation:

The receiver makes a decoding error only if three bits or two bits of a 3-bit string are sent wrongly.

Let's call

p = probability that one bit was sent incorrectly.

Since bit errors occur random and independently of each other, the probability that 3 bits are sent incorrectly is

$p\times p\times p=p^3$

Similarly, the probability that 2 bits are sent incorrectly is

$p\times p=p^2$

The probability that 3 or 2 bits are sent incorrectly is

$p^3+p^2$

So, all we have to do now is compute p.

Let x be the number of bits incorrectly transmitted per unit of time.

Since the channel operates at 3 Mbps (3,000,000 bits per second) and has a bit error rate of 0.001, then

$BitErrorRate=\frac{errors}{total bits}=\frac{x}{3,000,000}=0.001$

and

x = 3000

This means that for every 3 million bits transmitted, 3000 are wrong.

So, the probability p that one bit is incorrect when transmitted is

$p=\frac{3000}{3,000,000}=0.001$

(Remark: When the probability is measured as a number between 0 and 1, it can be shown that the bit error rate and the probability of sending one bit incorrectly are the same)

Hence the probability that the receiver makes a decoding error is

$0.001^3+0.001^2=1001\times 10^{-9}$

or in % notation

$1001\times 10^{-7}\%$

4 0

2 years ago