2 years ago

Can somebody help me please

Mathematics

1 answer:

BabaBlast [244]2 years ago

5 0

Answer:

Find the slope of the original line and use the point-slope formula

y−y1=m(x−x1) to find the line parallel to y=2x−7. y=2x+12

You might be interested in

Mitchell walked 5/12 of a mile in 1/2 of an hour. At this rate, how far could Mitchell walk in 1 hour?

vovangra [49]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$2 \times \frac{1}{2} hour = 1hour \\$

Thus ;

$2 \times \frac{5}{12} \: \: miles = \frac{10}{12} \: \: miles = \frac{5}{6} \: \: miles \\$

,♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6 0

2 years ago

Read 2 more answers

35% of f is 14. What is f? Enter your answer as a numeric expression.

Nata [24]

Answer:

Step-by-step explanation:

14/35 = f/100

35f = 14 x 100

f = 14 x 100 /35

f = 40

7 0

2 years ago

Read 2 more answers

For the remaining questions, show your work.

ser-zykov [4K]

Step-by-step explanation:

6a.

$- 5 = - 3 + a$

$- 2 = a$

6b.

$3c + 2 = - 22$

$3c = - 24$

$c = - 8$

5 0

2 years ago

Read 2 more answers

OLEASE DO THIS ITS EASY PKEAS EI NEED TO FINISH IT NOW PKEASE

KATRIN_1 [288]

For x y chart 19.36.2.27.13

8 0

2 years ago

describe the transformations that produce the graph of g(x)=1/2(x-4)^3+5 from the graph of the parent function f(x)=x^3. Give th

SSSSS [86.1K]

We have been given a parent function $f(x)=x^{3}$ and we need to transform this function into $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

We will be required to use three transformations to obtain the required function from $f(x)=x^{3}$ .

First transformation would be to shift the graph to the right by 4 units. Upon using this transformation, the function will change to $g(x)=(x-4)^{3}$ .

Second transformation would be to compress the graph vertically by half. Upon using the second transformation, the new function becomes $g(x)=\frac{1}{2}(x-4)^{3}$ .

Third transformation would be to shift the graph upwards by 5 units. Upon using this last transformation, we get the new function as $g(x)=\frac{1}{2}(x-4)^{3}+5$ .

6 0

3 years ago