$70.88
x/67.5=5/100
cross multiply
100x=337.5
divide 100
x=3.375 or 3.38
67.50+3.38= 70.88
13.1......... I believe this is the correct answer
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
3 2/5 3•5+2 17/5 3.4 11 3/20 223/20 11.15 +3.4=11.15
-3.4 -3.4
= 7.75
7.75+3.6 11.15
11.15=11.15