The circumference of a circle is C=2πR, where R is the radius of the circle and π≈3.14.
So if we open the circumference of the circle into a straight line segment, the length of this segment is C=2πR≈2*3.14*R=6.28R
4 rotations mean 4 circumferences that is 4 segments of length 6.28R,
which makes a linear distance of 4*6.28R=25.12R
i: the radius of the smaller wheel is R=r, thus it covers a distance of 25.12r feet
ii: the radius of the smaller wheel is R=2r, thus it covers a distance of 25.12*2r=50.24r (feet)
50.24r is twice 25.12r, thus the larger wheel traveled Twice the distance of the smaller one.
Answer: the larger covered twice the distance of the smaller.
Answer:
C
Step-by-step explanation:
Given :
A 136 foot tall cell phone tower casts a 79.9 foot shadow.
To Find :
The shadow length for a nearby 40 foot telephone pole .
Solution :
We know , the ratio of height and shadow , will be same for every object .
Let , length of shadow of pole is x .
So ,
Therefore , the length of shadow of tower is 23.5 foot .
Hence , this is the required solution .
Answer:
w <u>> </u> -6
Step-by-step explanation:
divide each term n 2x <u>> </u> -12 by 2 then simplify
Answer:
60
Step-by-step explanation:
0.25
2×5
10
0.25×10
=2.5
;4×6
=24
:2.5×24
=60
