Answer:
21.9°
Step-by-step explanation:
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
We solve this above question using the Sine rule
a/sin A = b/sin B
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.
Hence:
HI/∠J = JH/∠H
= 8/sin 90° = 1.9/sin ∠H
Cross Multiply
∠H = arc sin(sin 1.9 × 90/8)
∠H = 21.9°
X²+3x-21=0
1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2
2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21
Answer: the product of the 2 solutions of this equation is -21
Answer:
351.48cm²
Step-by-step explanation:
Heron’s Formula
Find half the perimeter (30+30+26)/2=43
It’s the square root of each side subtracted from 43, multiplied together, times 43.
√(43-30)*(43-30)*(43-26)*43=√13*13*17*43=√=123539=351.481cm²
Answer:
2/5 or 0.40
Step-by-step explanation:
Val's result for heads is ...
8/20 = 2/5 = 0.40