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2 years ago

When two lines crosses, it is found that the angle opposite each other are thesame sizes. They are known as what

Mathematics

1 answer:

Andreyy892 years ago

3 0

Answer:

vertical angles

Step-by-step explanation:

Opposite angles that are congruent are known as vertical angles.

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I really need help with this Triangle problem.

julia-pushkina [17]

Answer:

x = 10

y = 20

Step-by-step explanation:

$\tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20$

4 0

2 years ago

The dividend is a factor of 60. The divisor is a factor of 18. The quotient is a multiple of 3. Use the numbers to find one poss

Anna007 [38]

Answer:

The dividend is 360, divisor is 6 and quotient is 60.

Step-by-step explanation:

Factors of 3= 3*1

Factors of 18= 3*2*3

Factors of 60= 3*2*2*5

Taking LCM= 3*2*2*2*3*5= 360

60 is a factor of 360

The dividend is 360

If 360 is divided by 6 we get 60 which is a multiple of 3

and 6 is a factor of 18.

Therefore the dividend is 360 divisor is 6 and quotient is 60.

6 0

2 years ago

1) A clerk have y dollars, all in $10 bills. What expression repression the number of $10 bills the clerk has?

valina [46]

1) y:10;
2) 4p+6q;
3) x +( x+ 1) = 59 => 2x = 58 => x = 29 => 29 and 30;

4 0

2 years ago

Read 2 more answers

What is the product of 3.4 × 10−14 and 1.8 × 10^28?

DENIUS [597]

None of the answer matches the correct ans
(3.4×10-14)(1.8×10^28)
20(1.8×10^28)
3.6×10^29

8 0

3 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

2 years ago