What is the area of a square with side lengths of 9 feet? 81 ft 81 ft2 36 ft2 36 f
2 answers:
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We have:
4 triangles with the base b = 5ft and the height h = 6ft
4 rectangles with the lenght l = 5ft and the width w = 4ft
1 square with side a = 5ft.
The formula of an area of a riangle:
Substitute:
The formula of an area of a rectangle:
Substitute:
The formula of an area of a square:
Substitute:
The Surface Area of composite solid:
Substitute:
The solutions or roots so-called are really just the x-intercepts, and for a quadratic equation, the vertex is found right half-way between those x-intercepts.
we can get the intercepts by zeroing out "y" or f(x), so let's take a peek at one of those,
so, the x-intercepts or solutions are at 5 and -1, let's take a peek what's the halfway point.
-1----0----1---- 2 ----3-----4------5
well then, now we know the vertex is at x = 2, but, what's the y-coordinate of it anyway?
y = (x - 5)(x + 1)
y = (2 - 5)(2 + 1)
y = (-3)(3)
y = -9
we can get the intercepts by zeroing out "y" or f(x), so let's take a peek at one of those,
so, the x-intercepts or solutions are at 5 and -1, let's take a peek what's the halfway point.
-1----0----1---- 2 ----3-----4------5
well then, now we know the vertex is at x = 2, but, what's the y-coordinate of it anyway?
y = (x - 5)(x + 1)
y = (2 - 5)(2 + 1)
y = (-3)(3)
y = -9