The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...
The mean is centered among the other numbers in both sets of data.
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The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.
Answer:
the answer is 9×9 and -9×-9
Wrote as a fraction 563/1000
98.86-85.15= 13.71 This is the answer to the problem. It's really easy. U just subtract and that's it.