The expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
Given an integral .
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=
∑f(a+iΔx)Δx=
∑
=4∑
Hence the expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
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Answer:
(5/12)d - (23/36)g
Step-by-step explanation:
First you can eliminate g and -g to get (1/6)d - (3/4)g + (1/9)g + (1/4)d. Then you need to get common denominators to add like terms together.
1/6 = 4/24 and 1/4 = 6/24. Add them together to get (10/24)d or (5/12)d.
-3/4 = -27/36 and 1/9 = 4/36. Add them together to get (-23/36)g.
So in standard form, (5/12)d - (23/36)g
Answer: le quedan leer 295 páginas
Step-by-step explanation:
It's 180-50-50=180-100=80°
Answer:
12 liters
Step-by-step explanation:
Let the capacity sum of the 5 containers be X
13 = X / 5
X = 65 liters
Average capacity of the six = ( 65 + 7 )/ 6 liters
= 72/6 liters
= 12 liters