Joey is constructing the circumscribed circle for △RST. He has already used his compass and straightedge to complete the part of
the construction shown in the figure.
What could be his next step?
Place the point of the compass on point A and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point S and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point T and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point R and draw an arc intersecting the two arcs X and Y.
What could be his next step?
Place the point of the compass on point A and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point S and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point T and draw an arc intersecting the two arcs X and Y.
Place the point of the compass on point R and draw an arc intersecting the two arcs X and Y.
2 answers:
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Answer:
(i) 15 m, 6 m/s
(ii) 90 m
Step-by-step explanation:
(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...
d = (1/2)at^2
The distance covered by Ben in the 5 seconds he is accelerating is ...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Of course, Ben's speed at that point is ...
s = (1.2 m/s²)(5 s) = 6 m/s
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(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.
It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...
(22.5 s)(4 m/s) = 90 m . . . the distance OP
