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3 years ago

What is equation for the line that is perpendicular to y-3=-4(x+2) and passes through the point (-5,7)

Mathematics

1 answer:

jekas [21]3 years ago

4 0

Answer:

y-7=1/4(x+5)

Step-by-step explanation:

y-3=-4(x+2)

y=-4x-8+3

y=-4x-5

-----------

y-y1=m(x-x1)

y-7=m(x-(-5))

y-7=m(x+5)

perpendicular means negative reciprocal of the slope,

so the slope will be 1/4

y-7=1/4(x+5)

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F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function

Neporo4naja [7]

Answer:

$f(3) = 38$

Step-by-step explanation:

Given the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

Evaluating the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

substitute x = 3

$f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9$

$f(3) = 45-16+9$

$f(3) = 38$

Therefore,

$f(3) = 38$

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1 year ago

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#2. 1-> 0->3/9
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2 years ago

Which number (s) below represents a repeating decimal? -2/5, -7, 3/7, 11/12

Ray Of Light [21]

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Hope this helps! :D

-TanqR

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2 years ago

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