Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
(-1,5), (0,4) ,(1,3) ,(3,1) is linear so dont pick it
(-4,-7), (-2,-6), (2,-4), (4,-3) is linear
you know what I'll just say it wait a minute is there like a other option
Step-by-step explanation:
U can tell by graphing them out yourself and if u see a straight line then it linear, and if you see a curved loop then it's non- linear. but I'll do it :)
From the given options we can say that the only one that represents the area of the sector is; A = n/360 * πr²
<h3>What is the Area of the Sector?</h3>
In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.
The formula for Area of a sector is given as;
θ/360 * πr²
where;
θ is the central angle of the sector
r is radius
Now, looking at the given options we can say that the only one that represents the area of the sector is;
A = n/360 * πr²
where n is the central angle of the sector
Read more about Area of Sector at; brainly.com/question/16736105
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4(3-7x). Since there are 4 sides in a square, you multiply one length by 4 to get the perimeter. 4(3-7x) simplifys to 12-28x.
