Write the equation in standard form for the hyperbola with vertices (-8,0) and (8,0), and foci (-10,0) and (10,0).
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Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Answer:
See below
Step-by-step explanation:
<u>Given functions</u>
- f(x)=8^x
- g(x)=8^(x+5) + 1
As we see g(x) = f(x + 5) + 1, which means <u>horizontal translation 5 units left</u> and <u>vertical translation 1 unit up</u>.
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