<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
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I think the answer is A. Cause your supposed to subtract so 7n-4n=3n, and 3-2=1 :) I hope this helps
Answer: the bill for a hamburger is $0.7
the bill for a salad is $1.5
Step-by-step explanation:
Let x represent the bill for a hamburger.
Let y represent the bill for a salad.
The bill for five hamburgers and four salads is $9.50. This means that
5x + 4y = 9.5- - - - - - - - - - - - - - 1
The bill for four hamburgers and five salads is $10.30. This means that
4x + 5y = 10.3 - - - - - - - - - - - - - -2
Multiplying equation 1 by 4 and equation 2 by 5, it becomes
20x + 16y = 38
20x + 25y = 51.5
Subtracting, it becomes
- 9y = - 13.5
y = - 13.5/ - 9
y = 1.5
Substituting y = 1.5 into equation 1, it becomes
5x + 4(1.5) = 9.5
5x + 6 = 9.5
5x = 9.5 - 6 = 3.5
x = 3.5/5 = 0.7
Answer:
Step-by-step explanation:
The sample space is shown in the attached photo.
Probability = number of favourable outcomes/total number of outcomes.
Looking at the diagram, the total possible outcomes is 36.
A) from the diagram, the total number of events in which the sum of the numbers is odd is 18. Therefore, the probability that the sum of the numbers is odd is
18/36 = 1/2
B) the total number of events in which the sum of the numbers is 10 or more is 6. Therefore, the probability that the sum of the numbers is 10 or more is
6/36 = 1/6
C) the total number of events in which 3 appears on each of the two dice is 1. Therefore, the probability that 3 appears on each of the two dice is
1/36
Pemdas
parenthasees first
exponents
mult or div
add or subtract
parenthasees
(13-8)=5
now we have
53/5*2
left to right
53/5=10.6
10.6*2=21.2
it is 21.2