Answer:
Step-by-step explanation:
Given that a small business assumes that the demand function for one of its new products can be modeled by
Substitute the given values for p and x to get two equations in c and k
Dividing on by other we get
Substitute value of k in any one equation
b) Revenue of the product is demand and price
i.e. R(x) = p*x =
Use Calculus derivative test to find max Revenue
R'(x) =
EquateI derivative to 0
1-0.000589x =0
x = 1698.037
When x = 1698 and p = 16.56469
(x+3)(x-3)
x*x=x^2
x*-3=-3x
3*x=3x
3*-3=-9
where’s where he most likely messed up
x^2-3x+3x-9
the correct answer is x^-9
Answer:
This is not a dating app.
8ab-2b+ab-b
8ab+ ab= 9ab
-2b-b= -3b
Answer: 9ab - 3b
−3(1+x)=−3x+1
Step 1: Simplify both sides of the equation.
−3(1+x)=−3x+1
(−3)(1)+(-3)(X)=-3x+1
(Distribute)
−3+ −3x=−3x+1
−3x−3=−3x+1
Step 2: Add 3x to both sides.
−3x−3+3x=-3x+1+3x
−3=1
Step 3: Add 3 to both sides.
−3+3=1+3
0=4
Answer:
There are no solutions.