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2 years ago

Blank is the change in position of an object

Physics

1 answer:

mamaluj [8]2 years ago

6 0

Displacement is your answer :)

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How is velocity ratio of wheel and axle calculatedaad<br>

iogann1982 [59]

Answer:

VR = $\frac{Radius of wheel}{Radius of axle}$

Explanation:

A machine is a device that can be used to overcome a load by the application of an effort through a pivot. Examples are: pulleys, wedge, screw jack, wheel and axle etc.

The wheel and axle is a simple device that can be used to lift a load through a height. Its velocity ratio (VR) can be determined by:

VR = $\frac{Radius of wheel}{Radius of axle}$

Note that for a practical wheel and axle, the radius of the wheel is greater than the radius of the axle.

3 0

2 years ago

In your textbook reading Chapter 26, the author suggests that an electric vehicle (EV) fleet can be used as a kind of distribute

d1i1m1o1n [39]

Answer:

Answer for the question is given in the attachment.

Explanation:

Download pdf

8 0

2 years ago

When ___ attacks the surface of a metal, it becomes tarnished.

alexandr1967 [171]

Answer:corrosion (i believe)

Explanation:

6 0

2 years ago

Read 2 more answers

6. An object moves along the x-axis. The graph shows its position x as a function of time t. Find

raketka [301]

Answer: 1.5 m/s

Explanation:

9-3/5-1= 6/4= 3/2= 1.5

Used x2-x1/t2-t1 to get average velocity from point b to c

7 0

2 years ago

A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too

maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $90\times 1.989\times 10^{30}\ kg$

$R_{f}$ = 10000+100 m

$R_{sb}$ = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

$\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2$

The acceleration is 2352645198509.9604 m/s²

4 0

2 years ago