The solubility of nitrogen in water at 25 °C= 4.88 x 10⁻⁴ mol/L
<h3>Further explanation</h3>
Given
78% Nitrogen by volume
Required
The solubility of nitrogen in water
Solution
Henry's Law states that the solubility of a gas is proportional to its partial pressure
Can be formulated
S = kH. P.
S = gas solubility, mol / L
kH = Henry constant, mol / L.atm
P = partial gas pressure
In the standard 25 C state, the air pressure is considered to be 1 atm, so the partial pressure of N₂ -nitrogen becomes:
Vn / Vtot = Pn / Ptot
78/100 = Pn / 1
Pn = 0.78 atm
Henry constant for N₂ at 25 °c = 1600 atm/mol.L=6.25.10⁻⁴ mol/L.atm
The solubility :
Answer:
The new volume is 5.913*10^4 L
Explanation:
Step 1: Write out the formula to be used:
Using general gas equation;
P1V1 / T1 =P2V2 /T2
V2 = P1V1T2 / P2T1
Step 2: write out the values given and convert to standard unit's where necessary
P1 = 0.995atm
P2 0.720atm
V1 = 5*10^4 L
T1 = 32°C = 32+ 273 = 305K
T2 = -12°C = -12 + 273 = 261K
Step 3: Equate your values and do the calculation:
V2 = 0.995 * 5*10^4 * 261 / 0.720 * 305
V2 = 1298.475 * 10^4 / 219.6
V2 = 5.913 * 10^4 L
So the new volume of the balloon is 5.913*10^4 L
Answer:phosphates are insoluble in water
Explanation:
There is thermal energy, but temperature is also a measure of the average kinetic energy, so either of those should be acceptable answers for the question.
First. let's write the reaction formula: HBr +LiOH ----> LiBr + H₂O
let's get the moles of LiOH first
moles= Molarity x Liters
moles= 0.253 M x 0.01673 Liter= 0.00423 moles LiOH
using the balanced equation, you can see that 1 mol LiOH is equal to 1 mol HBr. so:
0.00423 mol LiOH = 0.00423 mol HBr
now let's find the concentration
molarity= mol/ Liters
0.00423 mol/ 0.01000 Liters= 0.423 M