The first table is proportional. Y is 4 times X. The second table is 1.25 times X
Ok so you have a equation already solved for a single variable which in this case is y. So just take 6x+2 and sub it in for all the y's in 3y-18x=12 3(6x+2)-18x=12. Now distribute the 3 to get 18x+6-18x=12. Next combine like terms to get 6=12 Now because we cant do anything else and our variable is canceled out and the equality of 6=12 is false the solution to this SoE would be No Solution. <span />
Solve for x. I'll do it by completing the square:
2x² = 4x + 9
2x² - 4x = 9
x² - 2x = 9/2
x² - 2x + 1 = 11/2
(x - 1)² = 11/2
x - 1 = ± √(11/2)
x = 1 ± √(11/2)
x = 1 ± √22/2
x = (2 ± √22)/2
Take the solution with the positive square root. Then it follows that a = c = 2 and b = 22. So a + b + c = 26.
3(a b c)2 so acc. To ques. 3(2×3×4)2
3(24)2 = 144
I mean I guess??????????????????????