Answer:
If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.
Answer:
A)$2.50 x b = total cost
B) 9 x 2.50 = $22.5
C) 50 x $2.50 = $125 - $14.75 = $110.25
Answer:
Step-by-step explanation:
Start
<F = <Q Given
<GPF = <RPQ Vertically opposite angles
<FGP = <QRP A triangle has 180 degrees. 2 equal angles means the third pair must be equal
Triangle GPF ~ Triangle RPQ AAA
end
I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.
20
JL/LE = 90/27 Given
KL /LD = 90/27 Given
<JLK = <DLK Vertically opposite
Are the ratios equal Yes Then is the angle included Yes
Then the triangles are similar.
Are the ratios not equal No then the triangles cannot be similar
Is the angle not included Then similarity cannot be proved.
ΔJLK ≈ ΔDLK Equal Ratios and included angle === similarity
Answer:
1.) Circumference of circle A = 131.95 metre
2.) Circumference of circle B = 175.93 metre
3.) Yes. Radius is proportional to the circumference.
Step-by-step explanation: Given that Circle A has a radius of 21 meters and Circle B has a radius of 28 meters
Circumference of a circle = 2πr
For circle A
Radius r = 21
Circumference = 2 × 3.143 × 21
Circumference = 131.95 metre
For circle B
Circumference = 2 × 3.143 × 28
Circumference = 175.93 metre
Is the relationship between the radius of a circle and the distance around the circle the same for all circles? YES
Because the radius of the circle is proportional to the distance around them ( circumference ) for all the circle. That is, the larger the radius, the larger the circumference
the answer is the first one y<0
