Answer:
a. [6.6350,7.3950]
b. ME=0.5150
Step-by-step explanation:
a. Given that n=40, 
and that:
The required 90% confidence interval can be calculated as:
![\bar x\pm(margin \ of \ error)\\\\\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\\\6.88\pm(1.645\times \frac{1.98}{\sqrt{40}})\\\\=[6.3650,7.3950]](https://tex.z-dn.net/?f=%5Cbar%20x%5Cpm%28margin%20%5C%20of%20%5C%20error%29%5C%5C%5C%5C%5Cbar%20x%5Cpm%20z_%7B%5Calpha%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C6.88%5Cpm%281.645%5Ctimes%20%5Cfrac%7B1.98%7D%7B%5Csqrt%7B40%7D%7D%29%5C%5C%5C%5C%3D%5B6.3650%2C7.3950%5D)
Hence, the 90% confidence interval for the population mean cash value of this crop is [6.6350,7.3950]
b. The margin of error at 90% confidence interval is calculated as:
Hence, the margin of error is 0.5150
Answer:
Equation: (x+9)² + (y+2)² = 100
4 points: (1, -2) (-1, 4), (-3, -10) (-19, -2)
(-3, 6) is on the circle
Step-by-step explanation:
(h, k) (-9, -2)
Equation: (x+9)² + (y+2)² = 100
4 points: (1, -2) (-1, 4), (-3, -10) (-19, -2)
(-3, 6) is on the circle
check: (-3 + 9)² + (6 + 2)² = 36 + 64 = 100 = 10²
Problem 12)
You are correct. You solve the system
x+1 = 3y
3x-4 = 5y+1
for x and y to find that x = 5 and y = 2
As a check
x+1 = 3y
5+1 = 3*2
6 = 6 ... true equation
and
3x-4 = 5y+1
3*5-4 = 5*2+1
11 = 11 ... true equation
Both equations are true when (x,y) = (5,2) so the answer is confirmed
=======================================================
Problem 13)
Unfortunately the diagram is cut off so its impossible to say at the moment. Please repost this one. Thank you.
Answer:
Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=5x+2 f - 1 ( x ) = 5 x + 2 is the inverse of f(x)=5x−2 f ( x ) = 5 x - 2 .
Step-by-step explanation:
Answer:
All positive real numbers
Step-by-step explanation:
Given
The model can be represented as:
Required
Determine the domain
This means that we list out possible values of x.
If x represents time, then it is impossible for x to be negative.
This implies that x can take any value as long as it is greater than or equal to 0.
<em>Hence, the domain is all positive real numbers</em>
