A 206.3 kg walrus initially at rest on a horizontal floor requires a 249 N horizontal force to set it in motion. Find the coeffi
1 answer:
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Answer:
Explanation:
a) Fundamental frequency
A harmonic is an integral multiple of the fundamental frequency.
b) Wave speed
(i) Calculate the wavelength
In a fundamental vibration, the length of the string is half the wavelength.
(b) Calculate the speed s
Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.