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To find the number of atoms in 2.822 moles of nickel, we need to multiply it by Avogadro's number. Avogadro's number is 6.02 x 10^23 atoms.
2.822 moles x (6.02 x 10^23) ≈ 1.698844 x 10^24
Therefore, there are about 1.70 x 10^24 atoms (according to the number of significant figures) in 2.822 moles of nickel.
Answer:
See attachment.
Explanation:
Elements that are in the same group will definitely possess similar characteristics because they tend to have the same valence electron which determines their reactivity.
On a periodic table, elements in the same group can be found arranged on the same column in the periodic table.
Therefore the two elements that have similar characteristics are those two elements you can see on the same column in group 2. See the two elements indicated in the attachment below.
111.1 mL of water
Explanation:
Weight per volume concentration (w/v %) is defined as
weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100
volume of solution = (mass of solute × 100) / weight per volume concentration
volume of solution = (1 × 100) / 0.9 = 111.1 mL
volume of water = volume of solution = 111.1 mL
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weight per volume concentration
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Answer:
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Explanation:
