Answer:
Step-by-step explanation:
Given: In parallelogram DEFG,
DH = x + 1
HF = 3y
GH = 3x - 4
and HE = 5y + 1
Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore
x+1=3y (1)
3x-4=5y+1 (2)
Multiply equation (1) with 3 and then subtract equation (2) from it, we get
3x+3-3x+4=9y-5y-1
7=4y-1
y=2
Substituting the value of y=2 in equation (1), we get
x+1=3(2)
x=5
Therefore, the value of x and y are 5 and 2 respectively.
Answer:
The simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.
Step-by-step explanation:
The expressions provided are:
(i)
Simplify the first expression with as few symbols as possible:
(ii)
Simplify the second expression with as few symbols as possible:
Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.
Distribute -3 in
-3x + 42 + 6x
3x + 42
Hope this helps!
Answer:
D. false; if a = 1, b = 2, and c = 3, then 1(2 + 3) ≠ 1(2) + 2(3)
Step-by-step explanation:
A is false, because the a is being distributed/ being multiplied to all terms inside the parenthesis, and not the term b.
B is also false. There is no indicated negative signs.
C is also false because 1(1 + 1) is EQUAL to 1(1) + 1(1)
D is true.